What is the electric potential just outside a hollow spherical shell of radius R and charge Q at a distance r > R?

Study for the Electrostatics Test. Utilize flashcards and multiple-choice questions, each accompanied by hints and explanations. Prepare thoroughly for this essential exam!

Multiple Choice

What is the electric potential just outside a hollow spherical shell of radius R and charge Q at a distance r > R?

Explanation:
Outside a hollow spherical shell with total charge Q, the symmetry makes the field behave as if all the charge were at the center. The electric field magnitude is E(r) = kQ / r^2 in the radial direction. The potential difference from infinity to r is V(r) - V(∞) = -∫∞^r E·dr, and with V(∞) = 0 this gives V(r) = ∫∞^r (kQ / t^2) dt = kQ / r. So the potential decreases like 1/r with distance, matching the field of a point charge at the center. The surface value would be kQ/R, but for any distance greater than R the correct expression is kQ/r. The other forms do not have the right 1/r distance dependence outside the shell.

Outside a hollow spherical shell with total charge Q, the symmetry makes the field behave as if all the charge were at the center. The electric field magnitude is E(r) = kQ / r^2 in the radial direction. The potential difference from infinity to r is V(r) - V(∞) = -∫∞^r E·dr, and with V(∞) = 0 this gives V(r) = ∫∞^r (kQ / t^2) dt = kQ / r. So the potential decreases like 1/r with distance, matching the field of a point charge at the center. The surface value would be kQ/R, but for any distance greater than R the correct expression is kQ/r. The other forms do not have the right 1/r distance dependence outside the shell.

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