For a capacitor, the voltage between plates is V = Q/C. If the charge Q is doubled while the capacitance stays the same, the voltage V:

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Study for the Electrostatics Test. Utilize flashcards and multiple-choice questions, each accompanied by hints and explanations. Prepare thoroughly for this essential exam!

Multiple Choice

For a capacitor, the voltage between plates is V = Q/C. If the charge Q is doubled while the capacitance stays the same, the voltage V:

Explanation:
Voltage between the plates is V = Q/C. With the capacitance fixed, V scales directly with the charge. Doubling the charge doubles the voltage. Physically, more charge on the plates strengthens the electric field between them, increasing the potential difference across the separation. The other outcomes would require changing the amount of charge in different ways (quarter, unchanged, or zero), which isn’t the scenario here.

Voltage between the plates is V = Q/C. With the capacitance fixed, V scales directly with the charge. Doubling the charge doubles the voltage. Physically, more charge on the plates strengthens the electric field between them, increasing the potential difference across the separation. The other outcomes would require changing the amount of charge in different ways (quarter, unchanged, or zero), which isn’t the scenario here.

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